Answer:
The reaction (E) 2 H₂O₂ (l) → O₂ g) + 2 H₂O (l) has a single species that is both oxidized and reduced.
Explanation:
Given the reaction (E):
2 H₂O₂ (l) → O₂ g) + 2 H₂O (l)
In hydrogen peroxide, oxygen has an oxidation state of -1. We can see that the reaction is balanced.
The products of the reaction are:
O₂ (the oxidation state of the Oxygen is 0)
H₂O (the oxidation state of the Oxygen is -2)
Hence, 1 mol of Oxygen changes its oxidation state from -1 to 0 (oxidation) and 1 mol of Oxygen changes its oxidation state from -1 to -2 (reduction).
The reaction (E) has a single species that is both oxidized and reduced.