Answer:
17
Step-by-step explanation:
We can put this as an AP (arithmetic progression).
The first number, after 160, that is divisible by 7 is:
161
The last number before 279 that is divisible by 7 is:
273
We can use the formula:
[tex]t_n=a+(n-1)d[/tex]
Where
tn is the nth term [here we take the last one, 273
a is the first term [161]
d is the common difference [7]
and n is the number of terms, we are trying to find this.
Substituting we get:
[tex]t_n=a+(n-1)d\\273=161+(n-1)(7)\\273=161+7n-7\\273=154+7n\\7n=119\\n=17[/tex]
Hence, there are 17 integers