Answer:
The answer to your question is: P2 = 846 kPa
Explanation:
Data
V1 = 2.5 l
P1 = 300 kPa
T1 = 273 °K
P2 = ?
V2 = 1 l
T2 = 308°K
Formula
[tex]\frac{P1V1}{T1} = \frac{P2V2}{T2}[/tex]
[tex]P2 = \frac{P1V1T2}{T1V2} \\[/tex]
[tex]P2 = \frac{(300)(2.5)(308)}{(273)(1)} \\[/tex]
[tex]P2 = \frac{231000}{273} \\[/tex]
P2 = 846 kPa