Answer:
The empirical formule of the substance is C5H12O
Explanation:
A substance contains 3 different elements
Carbon: 3.63 g
⇒ Molar mass of Carbon = 12g/mole
Hydrogen: 0.7615 g
⇒ Molar mass of hydrogen = 1g/mole
Oxygen: 1.028 g
⇒ Molar mass of oxygen = 16g/mole
Calculate number of moles
moles of hydrogen = 0.7615g / 1g/mole = 0.7615 moles
moles of carbon = 3.63g / 12g/mole = 0.3025 moles
moles of oxygen = 1.028g / 16g/mole = 0.06425 moles
Calculate ratio of moles
We divide by the smallest number of moles
Ratio of hydrogen= 0.7615/0.06425 ≈ 12
Ratio of carbon = 0.3025/ 0.06425 ≈ 5
Ratio of oxygen = 0.06425 / 0.06425 = 1
The empirical formule of the substance is C5H12O
