Respuesta :
Answer:
y = (25000)(1 + 0.15)^x
Step-by-step explanation:
This model is identical to the Compound Amount model except for the names of the variables used:
A = P(1 + r)^t becomes y = (25000)(1 + 0.15)^x,
where 0.15 is the annual interes rate as a decimal fraction and x is the number of years elapsed.
The required expression for the wolf to be increased by 15% yearly is, number of wolf y = 25000(1.15)^x.
Wolf are increasing by 15% per year. Expression for the increase in number of wolf to be determine.
What is exponential function?
Exponential function is defined as the variable degree of certain values. i.e. y=e^x.
Here, wolf are increasing by 15% every year shows that wolf increasing exponentially. So the factor at which that the wolfs are increasing is 1+0.15 = 1.15.
Now,
y = number of wolfs, x = year
y = 25000 (1.15)^x
Thus, the required expression for the wolf to be increased by 15% yearly is, number of wolf y = 25000(1.15)^x.
Learn more about exponential function here:
https://brainly.com/question/11487261
#SPJ2