Answer:
[tex]\large \boxed{\text{c. 13 s}}[/tex]
Explanation:
The formula relating distance (d), speed (s), and time (t) is
d = st
[tex]\begin{array}{rcl}\text{33 m} & = & \text{2.5 m$\cdot$s}^{-1}\times t\\t & = & \dfrac{33}{\text{2.5 s}^{-1}}\\\\& = & \textbf{13 s}\\\end{array}\\\text{The ball rolled for $\large \boxed{\textbf{13 s}}$}[/tex]
