Answer:
A. (x^2+4x-1)/(x(x+2))
Step-by-step explanation:
[tex]\dfrac{x+5}{x+2}-\dfrac{x+1}{x^2+2x}=\dfrac{x(x+5)}{x(x+2)}-\dfrac{x+1}{x(x+2)}=\dfrac{x(x+5)-(x+1)}{x(x+2)}\\\\=\dfrac{x^2+5x-x-1}{x(x+2)}=\dfrac{x^2+4x-1}{x(x+2)}[/tex]
... matches choice A.