Respuesta :

fgschem

Answer:

The hybridizations of the central atom in PO(OH)₃ is sp³.

Explanation:

The PO(OH)₃ has the central atom P making one double bond with an oxygen atom and three single bonds with the -OH.

The ligands are arranged in a tetrahedral geometry and the hybridization of the P atom is sp³. The charge is distributed asymetricaly and the molecule is polar.

A representation of the molecule can be seen in the figure attached.

Ver imagen fgschem

Answer : The hybridization of the central atom in [tex]PO(OH)_3[/tex]  is, [tex]sp^3[/tex]

Explanation :

Formula used  :

[tex]\text{Number of electron pair}=\frac{1}{2}[V+N-C+A][/tex]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the given molecule.

The given molecule is, [tex]PO(OH)_3[/tex]

[tex]\text{Number of electrons}=\frac{1}{2}\times [5+3]=4[/tex]

The number of electron pair are 4 that means the hybridization will be [tex]sp^3[/tex] and the electronic geometry of the molecule will be tetrahedral.

Hence, the hybridization of the central atom in [tex]PO(OH)_3[/tex]  is, [tex]sp^3[/tex]

Ver imagen Alleei

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