Which net ionic equation would match this description of a chemical reaction: When a
solution of magnesium nitrate is mixed with a solution of sodium phosphate, the solid that forms is magnesium phosphate.

a. Mg(NO3)2(aq) + Na2PO4(aq) à MgPO4(s) + NaNO3(aq)

b. Mg2+(aq) + PO43-(aq) à MgPO4(s)

c. 3Mg(NO3)2(aq) + 2Na3PO4(aq) à Mg3(PO4)2(s) + 6NaNO3(aq)

d. 3Mg2+(aq) + 2PO43- à Mg3(PO4)2(s)

e. 3Mg2+(aq) + 6NO3-(aq) + 6Na+(aq) + 2PO43- àMg3(PO4)2(s) + 6NO3-(aq) + 6Na+(aq)

It shuld be D correct?

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OrethaWilkison OrethaWilkison · Answer 1 · 2019-10-14T10:27:51+02:00

Answer:

[tex]3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)[/tex]

Explanation:

[tex]Mg(NO_{3})_{2}[/tex], [tex]Na_{3}PO_{4}[/tex] are strong electrolytes. Hence they are fully ionized in aqueous solution.

[tex]Mg_{3}(PO_{4})_{2}[/tex] is a sparingly soluble salt. Hence it remains undissociated in aqueous solution.

So, total ionic equation:

[tex]3Mg^{2+}(aq.)+6NO_{3}^{-}(aq.)+6Na^{+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)+6Na^{+}(aq.)+6NO_{3}^{-}(aq.)[/tex]

Net ionic equation is written by omitting spectator ions from total ionic equation.

Here, [tex]Na^{+}[/tex] and [tex]NO_{3}^{-}[/tex] ions are spectator ions as they remain present on both side of total ionic equation.

So, net ionic equation:

[tex]3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)[/tex]

So, option (d) is correct.