The expression $\sqrt{(\sqrt{56})(\sqrt{126})}$ can be simplified to $a\sqrt b$, where $a$ and $b$ are integers and $b$ is not divisible by any perfect square greater than 1. What is $a+b$?

Respuesta :

Answer:

  23

Step-by-step explanation:

[tex]\sqrt{\sqrt{56}\sqrt{126}}=\sqrt{\sqrt{7056}}=\sqrt{\sqrt{84^2}}\\\\=\sqrt{84}=2\sqrt{21}\\\\2+21=\bf{23}[/tex]

Answer:

23

Step-by-step explanation:

Since 56 is a multiple of 4 and 126 is a multiple of 9, we can factor squares out of both terms, getting $\sqrt{(2\sqrt{14})(3\sqrt{14})}=\sqrt{2\cdot3\cdot14}$. Then, we can factor $2^2$ out of the outer square root to get $2\sqrt{21}$. Thus $a=2$ and $b=21$, yielding $a+b=\boxed{23}$.