QueasyUnicorn14
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Need help ASAP!!
A stadium has 46,000 seats. Seats sell for ​$42 in Section​ A, ​$24 in Section​ B, and ​$18 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1,467,600 from each​ sold-out event. How many seats does each section​ hold?

Respuesta :

joseaaronlara

Answer:

The answer to your question is:

A = 23000

B = 14600

C = 8400

Step-by-step explanation:

Data

A = $42

B = $24

C = $18

                  A = B + C

Equations

                42A + 24B + 18C = 1,467,600

                A + B + C = 46,000

Process

                A + A = 46,000

               2A = 46000

               A = 23000

             B + C = 23000

             B = 23000 - C

              42(23000) + 24(23000 - C) + 18C = 1,467,600                  

             966000 + 552000 - 24C + 18C = 1467600

             -6C = -50400

              C = 8400

              B = 23000 - 8400

              B = 14600

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