Need help ASAP!!

A stadium has 49,000 seats. Seats sell for $30 in Section A, $24 in Section B, and $18 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,246,800 from each sold-out event. How many seats does each section hold?

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sqdancefan sqdancefan · Answer 1 · 2019-10-14T01:34:23+02:00

Answer:

Step-by-step explanation:

Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.

The revenue from those seats is, ...

24,500×$30 = $735,000

so the revenue from B and C seats is ...

$1,246,800 -735,000 = $511,800

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We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...

24b +18(24500-b) = 511800

6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms

b = 70,800/6 = 11,800 . . . . . . . seats in B section

24,500 -11,800 = 12,700 . . . . . seats in C section

There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.