Answer:
When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules
Solution:
We know [tex]\text { Work }(\mathrm{W})=\text { Force }(\mathrm{F})\times\text { Distance (D) }[/tex]
Anne is pushing the wheelbarrow with a force of 70 N at an angle of [tex]50^{\circ}[/tex] with the horizontal
So the force of Anne will be [tex]F=70 \cos 50^{\circ}=(70 \times 0.64)=44.8 \mathrm{N}[/tex]
She pushes the wheelbarrow 25 meter, So D = 25 meters
So, the [tex]work,F\times D=(44.8 \times 25)=1120 \text { Joules }[/tex]
Anne has done total 1120 joules work.
