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Omar invested his savings in two investment funds. The $6000 that he invested in Fund A returned a 3% profit. The amount that he invested in Fund B returned a 10% profit. How much did he invest in Fund B, if both funds together returned a 8% profit?

Respuesta :

osaruevbuomwan

Answer:

Investment in fund b = $15,000

Explanation:

Let us assume  funds invested in fund b = x while the sum total of funds invested in fund a & b = Y .ie Y = $6000 + x

Fund A returned $6000 * 3/100 = $180

Fund B returned = x & 10/100 = x/10

8%y(total returns) = funds a returns + fund b returns

8%y = $180 + (x/10)

let is replace y with 6000 + x

(6000 +x) * 8% = 180 + (x/10)

480+ 8x/100 = 180 + (x/10)

480 - 180 = (x/10) - (8x/100)

300 =        (10x - 8x )/100

300 = 2x/100

300*100 = 2x

30,000 = 2x

x = 15, 000

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