Answer: 12.83%
Step-by-step explanation:
Given : Sam measured the height of a window frame as 5.23 feet, but the actual height was 6 feet.
i.e. Estimated height = 5.23 feet
Actual height = 6 feet
Then, the percentage of error in Sam's measurement will be :-
[tex]\%\text{Error}=\dfrac{|\text{Estimated height-Actual height}|}{\text{Actual height}}\times100\\\\=\dfrac{|5.23-6|}{6}\times100\\\\ =\dfrac{0.77}{6}\times100\\\\=12.8333333333\approx12.83\%[/tex]
Hence, the percentage of error in Sam's measurement= 12.83%
