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Two samples of potassium iodide are decomposed into their constituent elements. The first sample produced 13.0 g of potassium and 42.3 g of iodine. If the second sample produce 24.4 kg of potassium, how many kg of iodine were produced?

Respuesta :

Answer:

79.4 kg

Explanation:

The formula for potassium iodide is:-

[tex]KI[/tex]

This means that they are present in the same mole ration, i.e. 1 : 1

Also for 2 samples, the ratio of the masses must be equal .

So,

[tex]\frac{Mass\ of\ potassium\ in\ sample\ 1}{Mass\ of\ Iodine\ in\ sample\ 1}=\frac{Mass\ of\ potassium\ in\ sample\ 2}{Mass\ of\ Iodine\ in\ sample\ 2}[/tex]

Thus,

Mass of potassium in sample 1 = 13.0 g

Mass of Iodine in sample 1 = 42.3 g

Mass of potassium in sample 2 = 24.4 kg

Applying in the above formula, we get that:-

[tex]\frac{13.0\ g}{42.3\ g}=\frac{24.4\ kg}{Mass\ of\ Iodine\ in\ sample\ 2}[/tex]

Mass of iodine in sample 2 = 79.4 kg

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