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Pregnancy length (in days) has a normal probability distribution with a mean of 266 days and a standard deviation of 16 days. What is the length of the pregnancy that marks the start of the 25th percentile? Enter a number rounded to two decimal places. Do not enter the units.

Respuesta :

Answer:

264.20

Step-by-step explanation:

Let X be the pregnancy length (in days)

Then X is N(266,16)

We can convert X to Z by

[tex]\frac{x-266}{16}[/tex]

[tex]Z=\frac{x-266}{16}[/tex] is N(0,1)

25th percentile for Z is

-0.675

Convert back to x score

[tex]x=-0.675(16)+275\\X =264.20[/tex]

25th percentile is 264.20

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