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When 50.0 g of 0.200 M NaCl(aq) at 24.1 °C is added to 100.0 g of 0.100 M AgNO3(aq) at 24.1 °C in a calorimeter, the temperature increases to 25.2 °C as AgCl(s) forms. Assuming the specific heat of the solution and products is 4.20 J/g °C, calculate the approximate amount of heat in joules produced.

Respuesta :

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Answer:

Q = 693 J

Explanation:

NaCl (aq) + AgNO₃ (aq) → AgCl (s) + NaNO₃ (aq)

Q = mcΔT

Q: heat

m: mass

c: specific heat

ΔT: temperature variation

Q = (50.0g + 100.0g) x (4.20 J/g°C) x (25.2°C - 24.1°C)

Q = 693 J

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