contestada

6t−20−32u6, t, minus, 20, minus, 32, u when t=6t=6t, equals, 6 and u=\dfrac14u=
4
1
​
u, equals, start fraction, 1, divided by, 4, end fraction.

Respuesta :

calculista

Answer:

8

Step-by-step explanation:

we have

[tex]6t-20-32u[/tex]

Evaluate the expression for

t=6 and u=1/4

Substitute the value of t and the value of u in the expression above

[tex]6(6)-20-32(1/4)[/tex]

[tex]36-20-8[/tex]

[tex]8[/tex]

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