A circuit consists of a series combination of 6.00 −kΩ and 4.50 −kΩ resistors connected across a 50.0-V battery having negligible internal resistance. You want to measure the true potential difference (that is, the potential difference without the meter present) across the 4.50 −kΩ resistor using a voltmeter having an internal resistance of 10.0 kΩ. What potentialdifference does the voltmeter measure across the 4.50-kΩresistor?

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fabianb4235 fabianb4235 · Answer 1 · 2019-11-06T05:24:21+01:00

Answer:

17.05V

Explanation:

Hello!

To solve this exercise we will use the following steps, the complete procedure attached an image.

1. Draw the complete circuit taking into account the configuration of the problem.

2. Remembering that the voltages in the nodes of the

Resistances connected in parallel are equal, we put them together using the sum of their inverses to find an equivalent resistance.

3. We find the current flowing in the circuit by taking the voltage from the source and dividing it by the total sum of resistances using Ohm's law

4. We use ohm's law again to find the voltage at the equivalent resistance.

Note: Ohm's law states that the voltage at a resistance is equal to the product of the current by the value of the resistance.

regards!