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Ariel left her home at 9 a.m., driving at 45 mph. At 11 a.m. her brother left the home and started after her at 60 mph. At what time did Ariel's brother catch up with Ariel?

Respuesta :

calculista

Answer:

5:00 pm

Step-by-step explanation:

Let

x -----> the umber of hours

y ----> the total distance in miles

we know that

The distance is equal to the speed multiplied by the time

Find out the distance traveled by Ariel at 11:00 am

11:00 am-09:00 am=2 hours

45(2)=90 miles

so

Ariel's linear equation is

[tex]y=45x+90[/tex] ----> equation A

Ariel's brother linear equation is

[tex]y=60x[/tex] ----> equation B

Equate equation A and equation B

[tex]60x=45x+90[/tex]

Solve for x

[tex]60x-45x=90[/tex]

[tex]15x=90[/tex]

[tex]x=6\ hours[/tex]

Adds 11:00 am + 6 hours=17:00 =5:00 pm

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