Answer:
The lines are perpendicular.
Step-by-step explanation:
We are given that on a coordinate plane
Line MN passing through (-4,8) and (-4,-6).
Line KL passing through (-8,2) and (6,2).
We have to find the relation between KL and MN.
Slope of line when line passing through the point[tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Using the formula
Slope of line MN=[tex]\frac{-6-8}{-4+4}=-\infty[/tex]
Slop of line KL=[tex]\frac{2-2}{6+8}=0[/tex]
Slope of line MN=[tex]-\frac{1}{slope\;of\;line\;KL}[/tex]
When slope of lines are reciprocal to each other then the lines are perpendicular.
Hence, line KL and MN are perpendicular.
Answer:The lines are perpendicular.
Answer:
Option 3.
Step-by-step explanation:
It is given that the line MN passes through the point (-4,8) and (-4,-6). The line KL passes through the points (-8,2) and (6,2).
If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the slope of the line is
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
The slope of the line MN is
[tex]m_{MN}=\frac{-6-8}{-4+4}=\infty[/tex]
It means line MN is a vertical line.
The slope of the line KL is
[tex]m_{KL}=\frac{2-2}{6-(-8)}=0[/tex]
It means line KL is a horizontal line.
Vertical and horizontal line are perpendicular. So, lines KL and MN are perpendicular.
Therefore, the correct option is 3.
