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A 50.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300 and the coefficient of kinetic friction is 0.200. What is the friction force on the box if (a) a horizontal 140-N push is applied to it?

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Answer:

98N and 147N

Explanation:

We have the following information:

[tex]m=50kg\\\mu_s =0.4\\\mu_k = 0.2\\F=140N[/tex]

We can find the static fricton force as follow,

[tex]F=\mu_s * N[/tex]

Where N is the normal force (mg)

[tex]F=0.3*50*9.8\\F=147N[/tex]

Static friction force at 147N is greater than the force applied hence body does not move.

[tex]F=\mu_k N = 0.2*50*9.8= 98N[/tex]

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