Answer:
C3 H6 Cl 3
Explanation:
C -24.2%
H - 4.0%
Cl - (100-24.2 - 4.0)=73.8 %
We can take 100g of the substance, then we have
C -24.2 g
H - 4.0 g
Cl - 73.8 g
Find the moles of these elements
C -24.2 g/12.0 g/mol =2.0 mol
H - 4.0 g/1.0 g/mol = 4. 0 mol
Cl - 73.8 g/ 35.5 g/mol = 2.1 mol
Ratio of these elements gives simplest formula of the substance
C : H : Cl = 2 : 4 : 2 = 1 : 2 : 1
CH2Cl
Molar mass (CH2Cl) = 1*12.0 +2*1.0 + 1*35.5 = 49.5 g/mol
Real molar mass = 150 g/mol
real molar mass/ Molar mass (CH2Cl) = 150 /49.5=3
So, Real formula should be C3 H6 Cl 3.
Answer: C3 H6 Cl3
Explanation:
Molecular formula = (Empirical formula)n
where n= num of moles
Then, let's calculate empirical formula
The molecule consists of Carbon (24.2%), Hydrogen (4.0%) and Chlorine (??)
The abundance of Chlorine is = 100% - ( 24.2% + 4.0%)
= 100% - 28.4%
= 71.8%
Therefore, we have, Carbon 24.2%, Hydrogen 4.0% and Chlorine 71.8%
C H Cl
24.2 4.0 71.8
divide each by mass its num 12 1 35.5
2 4 2
Divide through by the smallest 2 2 2
(i.e. 2) 1 2 1
Therefore, the empirical formula= CH2Cl
Molecular formular = (CH2Cl)n
But n = ??
(CH2Cl)n = 150; C=12, H=1, Cl=35.5
(12 + (2 x 1) + 35.5 )n = 150
(49.5)n = 150
n=3
Therefore, Molecular fromula = (CH2Cl)3
= C3 H6 Cl3
