contestada

PY85
How many grams of water at 85°C must be mixed with the 1000gm of water at 15°C so
that the final temperature of the mixture is 37°C?
[Ans: 4530ml
SS​

Respuesta :

MathPhys

Answer:

460 g

Explanation:

Heat lost by the warm water = heat gained by the cold water

-mCΔT = mCΔT

-m (4.184 J/g/K) (37°C − 85°C) = (1000 g) (4.184 J/g/K) (37°C − 15°C)

-m (37°C − 85°C) = (1000 g) (37°C − 15°C)

-m (-48°C) = (1000 g) (22°C)

m = 458 g

Rounded to two significant figures, you need a mass of 460 g of water.

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