Consider the following hypothesis test: H 0: 20 H a: < 20 A sample of 60 provided a sample mean of 19.5. The population standard deviation is 1.8. a. Compute the value of the test statistic (to 2 decimals). If your answer is negative, use minus "-" sign. b. What is the p-value (to 3 decimals)? c. Using = .05, can it be concluded that the population mean is less than 20? d. Using = .05, what is the critical value for the test statistic (to 3 decimals)? If your answer is negative, use minus "-" sign.

Respuesta :

Answer:

We reject the null hypothesis and accept the alternate hypothesis. Thus, it be concluded that the population mean is less than 20.          

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 60

Sample mean, [tex]\bar{x}[/tex] = 19.5

Sample size, n = 60

Alpha, α = 0.05

Population standard deviation, σ = 1.8

First, we design the null and the alternate hypothesis

[tex]H_{0}: \mu = 20\\H_A: \mu < 20[/tex]

We use One-tailed z test to perform this hypothesis.

Formula:

[tex]z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }[/tex]

Putting all the values, we have

[tex]z_{stat} = \displaystyle\frac{19.5 - 20}{\frac{1.8}{\sqrt{60}} } = -2.151[/tex]

Now, [tex]z_{critical} \text{ at 0.05 level of significance } = -1.64[/tex]

Since,  

[tex]z_{stat} < z_{critical}[/tex]

We reject the null hypothesis and accept the alternate hypothesis. Thus, it be concluded that the population mean is less than 20.