Answer:[tex]47\leq x\leq 100[/tex]
Step-by-step explanation:
Given
Steve's grade are 72, 75, 88, and 93
Steve's wish to earn Grade B in the course and this can occur when average of first five exam grades is greater than or equal to 75 and less than to 95
Suppose x be the score of last exam
average of 5 exams [tex]P_{avg} =\frac{72+75+88+93+x}{5}=\frac{328+x}{5}[/tex]
[tex]75\leq P_{avg}< 95[/tex]
[tex]75\leq \frac{328+x}{5}[/tex]
[tex]375-328\leq x[/tex]
[tex]47\leq x[/tex]
and [tex]\frac{328+x}{5} <95[/tex]
[tex]x <475-328[/tex]
[tex]x <147[/tex]
but highest grade is 100
therefore [tex]x \leq 100[/tex]
thus belongs to [tex]47\leq x\leq 100[/tex]