How well can you apply Boyle’s law to this sample of gas that experiences changes in pressure and volume? Assume that temperature and number of moles of gas are constant in this problem.

Using the first volume and pressure reading on the table as V1 and P1, solve for the unknown values in the table below. Remember to use the rules of significant figures when entering your numeric response.
A:
B:
C:
D:

According to the Boyle's law, the volume of a gas is inversely proportional to its volume. If we consider an initial state (1) and a final state (2):

P₁ × V₁ = P₂ × V₂

A

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = 3.0 atm × A

A = 1.0 L

B

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = B × 6.0 L

B = 0.50 atm

C

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = C × 5.0 L

C = 0.60 atm

D

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = 0.75 atm × D

D = 4.0 L

nishantwork777 nishantwork777 · Answer 2 · 2021-10-26T08:02:52+02:00

According to the Boyle's law, when the gas experience the change in pressure, its volume is also get affected, hence, the required value of :

[tex]A=1.0 L\\B=0.50 atm.\\C=0.60 atm.\\D=4.0 L[/tex]

Given information:

The Boyle's law states that the volume of a gas is inversely proportional to its pressure.

Hence, [tex]p_1\times v_1=p_2\times v_2[/tex]

Now for,

(A) Applying the Boyle's law:

[tex]p_1\times v_1=p_2\times v_2[/tex]

[tex]1.5\times2.0=3.0\times A\\A=1.0[/tex]

(B) Applying the Boyle's law:

[tex]p_1\times v_1=p_2\times v_2[/tex]

[tex]1.5\times 2.0=B\times6.0\\B=0.50[/tex]

(C)Applying the Boyle's law:

[tex]p_1\times v_1=p_2\times v_2[/tex]

[tex]1.5\times2.0=C\times5.0\\C=0.60[/tex]

(D)Applying the Boyle's law:

[tex]p_1\times v_1=p_2\times v_2[/tex]

[tex]1.5\times2.0=0.75\times D\\D=4.0[/tex]

Hence, according to the Boyle's law, the required value of:

[tex]A=1.0 L\\B=0.50 atm.\\C=0.60 atm.\\D=4.0 L[/tex]

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