Answer:
0.258 mg of iron remains.
Explanation:
To solve this problem we can use the formula
M₂ = M₀ * [tex]0.5^{\frac{t}{44.5} }[/tex]
Where M₂ is the mass remaining, M₀ is the initial mass, and t is time in days.
Using the data given by the problem:
M₂ = 2.000 mg * [tex]0.5^{\frac{133.5}{44.5} }[/tex]
M₂ = 0.258 mg
