2074 Set B Q.No. 1 What mass of nitrogen will be requires
produce 6.022 x 1024 molecules of ammonia by the follow
reaction?
N2 + 3H2 -- > 2NH3
Ans: 1.4*11​

Respuesta :

140 g of nitrogen (N₂)

Explanation:

We have the following chemical equation:

N₂ + 3 H₂ -- > 2 NH₃

Now, to find the number of moles of ammonia we use the Avogadro's number:

if        1 mole of ammonia contains 6.022 × 10²³ molecules

then   X moles of ammonia contains 6.022 × 10²⁴ molecules

X = (1 × 6.022 × 10²⁴) / 6.022 × 10²³

X = 10 moles of ammonia

Taking in account the chemical reaction we devise the following reasoning:

If        1 mole of nitrogen produces 2 moles of ammonia

then  Y moles of nitrogen produces 10 moles of ammonia

Y = (1 × 10) / 2

Y = 5 moles of nitrogen

number of moles = mass / molecular weight

mass = number of moles × molecular weight

mass of nitrogen (N₂) = 5 × 28 = 140 g

Learn more about:

Avogadro's number

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