Answer:
An equivalent system of equations is the option C
Step-by-step explanation:
we have the following system
[tex]Fx + Gy = H[/tex] -----> equation A
[tex]Qx + Ry = S[/tex] -----> equation B
Remember that
The Multiplication Property of Equality states that if you multiply both sides of an equation by the same number, the sides remain equal
so
Multiply the equation A by 5 both sides
[tex]5(Fx + Gy) = 5(H)[/tex]
Distributive property
[tex]5Fx + 5Gy = 5H[/tex] ----> equation C
Now we have the equivalent system of equations
[tex]5Fx + 5Gy = 5H[/tex] ----> equation C
[tex]Qx + Ry = S[/tex] -----> equation B
therefore
An equivalent system of equations is the option C
