Answer: a) 27.5, b) 5.33.
Step-by-step explanation:
Since we have given that
[tex]\mu =27.5\\\\\sigma =71.5[/tex]
and n = 180
We need to calculate the sample mean and sample standard deviation.
So, the mean of the distribution of sample means is
[tex]\mu = \mu_x=27.5[/tex]
The standard deviation of the distribution of sample means is
[tex]s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{71.5}{\sqrt{180}}=5.329=5.33[/tex]
Hence, a) 27.5, b) 5.33.
