Answer:
The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )
Step-by-step explanation:
Given equation as :
3 x² + 6 x +15 = 0
The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as
x = [tex]\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}[/tex]
So , from given eq , the value of x is now obtain as
x = [tex]\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}[/tex]
Or, x = [tex]\frac{-6\pm \sqrt{6^{2}-4\times 3\times 15}}{2\times 3}[/tex]
Or, x = [tex]\frac{\sqrt{-144} }{6}[/tex]
∴ x = ( - 1 + 2 i ) , ( - 1 - 2 i )
Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i ) Answer
