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How much heat is required to vaporize 50.0 g of acetone (C3H6O) at 25 ∘C? The heat of vaporization for acetone at this temperature is 31.0 kJ/mol

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Answer:

26.7 kJ/mol

Explanation:

  • Heat required = Heat of vaporization * moles

We're given the Heat of vaporization, so now we need to find the moles of acetone, to do that we'll use the given mass:

  • Molar mass of acetone (C₃H₆O) = 12*3 + 6*1 + 16 = 58 g/mol
  • 50.0 g acetone ÷ 58 g/mol = 0.862 mol acetone

Now we calculate the heat required:

  • Heat required = 31.0 kJ/mol * 0.862 mol
  • Heat required = 26.7 kJ/mol

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