Respuesta :
Answer :
(a) The angular speed of this bacterial motor is [tex]1.6\times 10^3s^{-1}[/tex]
(b) The time taken by the motor to make one revolution is [tex]3.9\times 10^{-3}s[/tex]
Explanation :
(a) To determine the angular speed of this bacterial motor.
Angular speed : It is defined as the rate at which an object changes its angle.
Formula used :
[tex]\omega=\frac{v}{r}[/tex]
where,
[tex]\omega[/tex] = angular speed
v = tangential speed = [tex]2.1\times 10^{-5}m/s[/tex]
r = radius = [tex]1.3\times 10^{-8}m[/tex]
Now put all the given values in the above formula, we get:
[tex]\omega=\frac{2.1\times 10^{-5}m/s}{1.3\times 10^{-8}m}[/tex]
[tex]\omega=1.6\times 10^3s^{-1}[/tex]
Thus, the angular speed of this bacterial motor is [tex]1.6\times 10^3s^{-1}[/tex]
(b) to determine the time taken by the motor to make one revolution.
Formula used :
[tex]T=\frac{2\pi}{\omega}[/tex]
where,
T = time
Now put all the given values in this formula, we get:
[tex]T=\frac{2\times 3.14}{1.6\times 10^3s^{-1}}[/tex]
[tex]T=3.9\times 10^{-3}s[/tex]
Thus, the time taken by the motor to make one revolution is [tex]3.9\times 10^{-3}s[/tex]
