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The slope of the line that represents the existing beam is -2/3. What equation could the architect use to represent a second beam whose graph passes through the corner at (0,10) and be parallel to the existing beam? Give you answer in
slope-intercept form.

Respuesta :

Answer:

y = -2/3x + 10

Step-by-step explanation:

m = -2/3 (parallel lines have the same slope)

Passes through (0,10)

Use point slope formula (y-y1) = m(x-x1)

y-10 = -2/3(x - 0)

Now distribute and solve for y to change to slope-intercept form y = mx+b

y-10 = -2/3x + 0

y = -2/3x +10

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