Given the system of inequalities:


4x – 5y < 1

One-halfy – x < 3





Which shows the given inequalities in slope-intercept form?


y < Four-fifthsx – One-fifth

y < 2x + 6

y > Four-fifthsx – One-fifths

y < 2x + 6

y > Negative four-fifthsx + One-fifth

y > 2x + 6

Respuesta :

Answer:

[tex]4x-5y<1[/tex] slope intercept form is option 3 - [tex]y>\frac{4x}{5}-\frac{1}{5}[/tex]

[tex]\frac{1}{2}y-x<3[/tex] slope intercept form is option 4 - [tex]y<2x+6[/tex]

Step-by-step explanation:

Given : The system of inequalities [tex]4x-5y<1[/tex] and [tex]\frac{1}{2}y-x<3[/tex]

To find : Which shows the given inequalities in slope-intercept form?

Solution :

The slope intercept form is [tex]y=mx+b[/tex] where m is the slope and b is y-intercept.

First inequality is [tex]4x-5y<1[/tex]

Now we take y to one side by subtracting 4x both side,

[tex]-5y<1-4x[/tex]

Divide both side by 5,

[tex]-y<\frac{1-4x}{5}[/tex]

Multiply both side by -1,

[tex]y>-\frac{1-4x}{5}[/tex]

[tex]y>\frac{4x-1}{5}[/tex]

[tex]y>\frac{4x}{5}-\frac{1}{5}[/tex]

So, Option 3 is correct.

Second inequality is [tex]\frac{1}{2}y-x<3[/tex]

Now we take y to one side by adding x both side,

[tex]\frac{1}{2}y<3+x[/tex]

Multiply both side by 2,

[tex]y<2(3+x)[/tex]

[tex]y<6+2x[/tex]

[tex]y<2x+6[/tex]

So, Option 4 is correct.

Answer:

y >_4/5x – 1/5 ; greater than or equal to symbol next to the y

y < _2x + 6; less than or equal to symbol next to the y

Step-by-step explanation: