Answer:
3h12min
Explanation:
We need to apply our thermodynamics concepts to find the required time in which the ice will melt at a given temperature.
In our data we have defined that,
[tex]\rho_f = 700kg/m^3[/tex]
[tex]hs_f = 334kJ/kg[/tex]
Performing an energy balance you have to:
[tex]E_{in} - E_{out} = E_{T}[/tex]
Internal energy is given by,
[tex]qA_sdt = dU[/tex]
[tex]A_s*h(T_{\infty}-T_f)dt = -\rho_f A_shs_fdx[/tex]
Integrating,
[tex]h(T_{\infty}-T_f)\int\limit^{t_m}_0dt = -\rho_fhs_f\int^0_{x_0}dx[/tex]
[tex]t_m = \frac{\rho hs_fx_0}{h(T_{\infty}-T_f)}[/tex]
Replacing the values,
[tex]t_m = \frac{(700)(334*10^3)(0.002)}{2(20-0)}[/tex]
[tex]t_m = 11.690s[/tex]
[tex]t_m \approx 3h12min[/tex]
Note: It was assumed that fros is isothermal and the radiation exchange is also negligible.