0.0024 g of Ba(NO₃)₂
Explanation:
First we need to determine the molecular weight of barium nitrate Ba(NO₃)₂
molecular wight of Ba(NO₃)₂ = molecular weight of Ba × number of Ba atoms + molecular weight of N × number of N atoms + molecular weight of O × number of O atoms
molecular wight of Ba(NO₃)₂ = 137 × 1 + 14 × 2 + 16 × 6 = 261 g/mol
number of moles = mass / molecular weight
mass = number of moles × molecular weight
mass of Ba(NO₃)₂ = 0.625 / 261 = 0.0024 g
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