Answer:
0.456033049
Explanation:
[tex]F=\mu N[/tex] where N=mg hence
[tex]F=\mu mg[/tex] where m is mass of object, g is acceleration due to gravity whose value is taken as [tex]9.81 m/s^{2}[/tex], [tex]\mu[/tex] is the coefficient of static friction and F is the applied force.
Making [tex]\mu[/tex] the subject we obtain
[tex]\mu=\frac {mg}{N}[/tex] and substituting m for 38 Kg, g for [tex]9.81 m/s^{2}[/tex] and 170 N for F we obtain
[tex]\mu=\frac{170} {38*9.81}=0.456033049[/tex]
Therefore, the coefficient of static friction is 0.456033049
