Answer:
a. Discriminant = 4
b. x = 1 and [tex]x = \frac{1}{2}[/tex]
Step-by-step explanation:
The Sridhar Acharya Formula gives if ax² + bx + c = 0, the then the roots of the equation is given by
[tex]x = \frac{-b +\sqrt{b^{2}-4ac } }{2a}[/tex] and [tex]x = \frac{-b -\sqrt{b^{2}-4ac } }{2a}[/tex]
In this solution the term [tex](b^{2} -4ac)[/tex] is called the discriminant of the original quadratic equation.
Now, in our case the equation is 4x² - 6x + 2 = 0
a. Therefore, the discriminant of this equation is = (-6)² - 4 × 4 × 2 = 4
b. The solutions of the equation are
[tex]x= \frac{-(-6) +\sqrt{4} }{2 \times 4}=1[/tex]
and [tex]x= \frac{-(-6) -\sqrt{4} }{2 \times 4}=\frac{1}{2}[/tex] (Answer)
