contestada

A pedestrian walks at a rate of 6 km per hour East. The wind pushes him northwest at a rate of 13 km per hour. Find the magnitude of the resultant vector.
(Round to the nearest hundredth)

Respuesta :

musiclover10045

The pedestrian vector would be (6,0)

The wind vector would be (-13cos(45), 13sin(45))  =  (-9.1924, 9.1924)  

Now add the two vectors:  (6, 0) + (-9.1924, 9.1924)  =  (-3.1924, 9.1924)    

This is the resultant vector in rectangular coordinates.   Now calculate the magnitude of the vector.

 

Magnitude is always positive and  is : sqrt[x-coord2 + y-coord2]  

 

Magnitude = sqrt(94.6915599) = 9.73 ( rounded to the nearest hundredth)

bartolosaul6

Answer: The answer on top is wrong warning the answer is actually 97.4

Otras preguntas