Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all males. Men have hip breadths that are normally distributed with a mean of 14.2 in. And a standard deviation of 0.9 in. Find P99 that is, find the hip breadth for men that separates the smallest 99% from the largest 1%

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Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. Men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1 inch. find P98. I really don't understand, help needed please.

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Find the z-value with a left tail of 0.98

invNorm(0.98) = 2.0537

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Find the corresponding x-value using x = zs+u

 

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x = 2.0537*1+14.4

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x = 16.45 inches

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The hip breadth for men is 16.45 inches.

What is z- distribution?

A unique type of normal distribution with a mean of 0 and a standard deviation of 1 is known as the standard normal distribution or z-distribution. By transforming the values of any normal distribution into z-scores, it is possible to standardize it. Z-scores indicate the number of standard deviations from the mean that each value falls within.

Given:

the z-value with a left tail of 0.98

invNorm(0.98) = 2.0537

the corresponding x-value using x = zs+u

x =[tex]2.0537*1+14.4[/tex]

x = 16.45 inches

Therefore, The hip breadth for men is 16.45 inches.

To know more about z-distribution refer to :

https://brainly.com/question/24213960

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