Answer:
[tex]-4\dfrac{17}{27}[/tex]
Step-by-step explanation:
We are asked to calculate the value of [tex]-1\dfrac{2}{3}[/tex] to the third power.
Now, [tex](-1\dfrac{2}{3})^{3}[/tex]
= [tex](-\dfrac{5}{3} )^{3}[/tex]
= [tex](-\dfrac{5}{3} ) \times (-\dfrac{5}{3} )\times (-\dfrac{5}{3} )[/tex] { Since we know, a³ = a × a × a }
= [tex]-\dfrac{5^{3} }{3^{3} }[/tex] { Since the product of three negative numbers is also negative }
= [tex]-\frac{125}{27}[/tex]
= [tex]-4\dfrac{17}{27}[/tex] ( Answer )
