Answer:
dh/dt = 0.318 in/min
Explanation:
Given that
dV/dt = 16 in³/min
Volume of the cylindrical pot
V= πr²h
r=radius
h=height
Given that
d=h= 8 in
h= 2 r
radius of cylinder r= 4 in
V= πr²h
V= 16πh
By differentiating with respect to time t
dV/dt = 16π dh/dt
Given that
dV/dt = 16 in³/min
16 in³/min= 16π dh/dt
dh/dt = 0.318 in/min