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Something is thrown in the air and 5.35 seconds later it lands on something 2.1 meters from the ground. How fast was it thrown up?

Respuesta :

MathPhys

Answer:

26.6 m/s

Explanation:

Given:

Δy = 2.1 m

t = 5.35 s

a = -9.8 m/s²

Find: v₀

Δy = v₀ t + ½ at²

(2.1 m) = v₀ (5.35 s) + ½ (-9.8 m/s²) (5.35 s)²

v₀ = 26.6 m/s

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