Answer:
The specific heat of water is Cp = 4.184 [tex]\frac{J}{g.^{o}C}[/tex]
Explanation:
1. The specific heat can be expressed as:
[tex]Cp=\frac{Q}{m(T_{2}-T_{1})}[/tex]
where Q is the energy, m is the mass of water, and T2-T1 express the change in the temperature.
2. Replace values for mass, energy and temperature:
[tex]Cp=\frac{16.736J}{(2.000g)*2.000^{o}C}}[/tex]
3. Solve the equation to obtain the specific heat of water:
Cp=4.184[tex]\frac{J}{g.^{o}C}[/tex]
