Answer:
L=31.9 mm
δ = 0.22 mm
Explanation:
Given that
v= 14 m/s
ρ=997 kg/m³
μ= 0.891 × 10⁻3 kg/m·s
As we know that when Reynolds number grater than 5 x 10⁵ then flow will become turbulent.
[tex]Re=\dfrac{\rho vL}{\mu}[/tex]
[tex]L=\dfrac{Re\mu}{\rho v}[/tex]
[tex]L=\dfrac{5\times 10^5\times 0.891\times 10^{-3}}{ 14 \times 997}\ m[/tex]
L=0.0319 m
L=31.9 mm
The thickness of the boundary layer at that location L given as
[tex]\delta =\dfrac{5L}{\sqrt{Re}}[/tex]
[tex]\delta =\dfrac{5\times0.0319}{\sqrt{5\times 10^5}}[/tex]
δ = 0.00022 m
δ = 0.22 mm
