Answer:
The answer to your question is: I(dB) = 320
Step-by-step explanation:
Data
I(dB) = 10log([tex]\frac{I}{Io}[/tex])
I = intensity of a given sound
Io = hearing intensity
if I = 10³²(Io) find I(dB)
Process
Substitute the value of I in the equation given and simplify using logarithms rules.
l(dB) = [tex]10 log \frac{10^{32}Io }{Io}[/tex]
Eliminate Io
I(dB) = 10 log (10³²)
Use the rule of powers in logarithms
I(dB) = 10(32)log(10)
l(dB) = 320(1)
I(dB) = 320
