Answer:
The nth term of the given sequence is given by a(n) = -3(1 + n)
Step-by-step explanation:
The given AP sequence is -6, -9, -12, -15, ...
Here, the first term = -6
The common difference (d) = a 2 - a 1
= -9 - (-6) = -9 + 6
= -3
⇒ d = - 3
Now, nth term of the Arithmetic Sequence is [tex]a_n = a+ (n-1)d[/tex]
⇒ a(n) = -6 + (n-1) (-3)
= -6 -3n + 3
= -3 - 3n
or, a(n) = -3(1 + n)
Hence, the nth term of the given sequence is given by a(n) = -3(1 + n)
